原来直接这么写就可以
[[UIApplication sharedApplication]openURL:[NSURL URLWithString:@"https://apps.apple.com/cn/app/idxxxxxx"]]
今天偶然间发现无法跳转
想要跳转现在需要另外加上一层判断,即:
if ([[UIApplication sharedApplication]openURL:[NSURL URLWithString:@"https://apps.apple.com/cn/app/idxxxxxx"]]) {
[[UIApplication sharedApplication]openURL:[NSURL URLWithString:@"https://apps.apple.com/cn/app/idxxxxxx"]];
}