shell脚本git批量拉取代码

前言：此代码只可做参照，因每个项目不同，拉取代码的方式不同

此项目有多个服务（微服务架构）：pay-parent-pom pay-soa-base pay-spi 等.....。因此更新每个服务需要将服务git pull，很费时间，所以写了此shell脚本，一键更新所有的服务至最新。

思想：遍历所有的dirs服务列表，一个个命令更新执行。

代码如下1：

dirs=(pay-parent-pom pay-soa-base pay-spi pay-soa-spi pay-soa-framework soa-proxy-client pay-soa-gateway pay-soa-channel pay-soa-wallet basic-soa-pay pay-notify-web pay-notify-router pay-soa-risk pay-job pay-cron-job pay-risk-job pay-kms-spi pay-kms-client pay-soa-card)

for i in "${dirs[@]}";

do

    #mkdir $i

    #cd $i

    echo Pull `pwd start build..........................`...

    git clone http://gitlab.hq.com/pay/$i.git

    #git checkout master

    git pull -v

    #cd ..

done

代码如下2：（高级）

#!/usr/bin/expect

set timeout 10

set host "1.1.41.109"

set username "jiangjiahao"

set password "password "

dirs=(pay-parent-pom pay-soa-base pay-spi pay-soa-spi pay-soa-framework soa-proxy-client pay-soa-gateway pay-soa-channel pay-soa-wallet basic-soa-pay pay-notify-web pay-notify-router pay-soa-risk pay-job pay-cron-job pay-risk-job pay-kms-spi pay-kms-client pay-soa-card)

for i in "${dirs[@]}";

do

mkdir $i

    cd $i

    echo Pull `pwd start build..........................`...

    git checkout master

    expect "Username for 'http://gitlab.h.com'" {send "$username\r"}

    expect "Password for 'https://jiangjiahao@gitlab.hqygou.com'" {send "$password\r"}

    interact

    git pull -v

    cd ..

done