def add(a, b):
print(f"ADDING {a} + {b}")
return a + b
def subtract(a, b):
print(f"SUBTRACTING {a} - {b}")
return a - b
def multiply(a, b):
print(f"MULTIPLYING {a} * {b}")
return a * b
def divide(a, b):
print(f"DIVIDING {a} / {b}")
return a / b
print("Let's do some math with just functions!")
age = add(30, 5)
height = subtract(78, 4)
weight = multiply(90, 2)
iq = divide(100, 2)
print(f"Age: {age}, Height: {height}, Weight: {weight}, IQ: {iq}")
# A puzzle for the extra credit, type it in anyway.
print("Here is a puzzle.")
what = add(age, subtract(height, multiply(weight, divide(iq, 2))))
print("That becomes: ", what, "Can you do it by hand?")
练习
- 如果你不是很确定return的功能，尝试自己写几个函数出来，让它们返回一些值。你可以将任何可以放在=右边的东西作为一个函数的返回值。
- 这个脚本的结尾是一个迷题。我将一个函数的返回值用作了另外一个函数的参数。我将它们连接一起，就像写数学等式一样。这样可能有些难懂，不过运行一下你就知道结果了。你可以试试看能不能用正常的方法实现和这个表达式一样的功能。
- 一旦你解决了这个迷题，试着修改一下函数里的某些部分，然后看会有什么样的结果。你可以有目的地修改它，让它输出另外一个值。
- 颠倒过来再做一次。写一个简单的等式，使用相同的函数来计算它。
答案
这个计算是从里到外的
def add(a, b):
print(f"ADDING {a} + {b}")
return a + b
def subtract(a, b):
print(f"SUBTRACTING {a} - {b}")
return a - b
def multiply(a, b):
print(f"MULTIPLYING {a} * {b}")
return a * b
def divide(a, b):
print(f"DIVIDING {a} / {b}")
return a / b
print("Let's do some math with just functions!")
age = add(30, 5)
height = subtract(78, 4)
weight = multiply(90, 2)
iq = divide(100, 2)
print(f"Age: {age}, Height: {height}, Weight: {weight}, IQ: {iq}")
# A puzzle for the extra credit, type it in anyway.
print("Here is a puzzle.")
first = divide(iq, 2)
second = multiply(weight, first)
third = subtract(height, second)
what = add(age, third)
print("That becomes: ", what, "Can you do it by hand?")
# 这是练习3的答案
practice = subtract(age, divide(height, divide(weight, add(iq, 2))))
print(practice)
公式：7-(5/(4+3*(2+1)))
def add(a, b):
return a + b
def subtract(a, b):
return a - b
def multiply(a, b):
return a * b
def divide(a, b):
return a / b
number = subtract(7, add(4, multiply(3, add(2, 1))))
print(f"the answer is {number}")
