重要知识点

一个题：
输入：

t m n -> t组 m * n 的矩阵 grid，
* 每组调用 func(grid) 函数打印出这个矩阵的所有元素和
* 
* 输入：
* 3 2 3
* 1 2 3
* 4 5 6
* 7 8 9
* 1 1 1
* 2 2 2
* 3 3 3
* 输出：|23 22 13|

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in.hasNext()) {
            int t = in.nextInt();
            int m = in.nextInt();
            int n = in.nextInt();
            int[] res = new int[t];
            int index = 0;
            while (t > 0) {
                t--;
                int[][] grid = new int[m][n];
                for (int i = 0; i < m; ++i) {
                    for (int j = 0; j < n; j++) {
                        grid[i][j] = in.nextInt();
                    }
                }
                res[index++] = func(grid);
            }
            for(int k = 0; k < res.length; k++){
                if(k == 0){
                    System.out.print(res[k]);
                }else{
                    System.out.print(" " + res[k]);
                }
            }
        }
        in.close();
    }

    private static int func(int[][] grid) {
        int sum = 0;
        for(int i = 0; i < grid.length; i++){
            for(int j = 0; j < grid[0].length; j++){
                sum += grid[i][j];
            }
        }
        return sum;
    }
}