最近用到在list中找出重复的元素，实现结果给大家分享一下，自己也当做一个笔记。
在网上找的布隆过滤器（BloomFilter）类的实现：

public class BloomFilter {
    private static final int DEFAULT_SIZE = 2 << 24;
    private static final int[] seeds = new int[] { 5, 7, 11, 13, 31, 37, 61 };
    private BitSet bits = new BitSet(DEFAULT_SIZE);
    private SimpleHash[] func = new SimpleHash[seeds.length];

    public BloomFilter() {
        for (int i = 0; i < seeds.length; i++) {
            func[i] = new SimpleHash(DEFAULT_SIZE, seeds[i]);
        }
    }

    public void add(String value) {
        for (SimpleHash f : func) {
            bits.set(f.hash(value), true);
        }
    }

    public boolean contains(String value) {
        if (value == null) {
            return false;
        }
        boolean ret = true;
        for (SimpleHash f : func) {
            ret = ret && bits.get(f.hash(value));
        }
        return ret;
    }

    // 内部类，simpleHash
    public static class SimpleHash {
        private int cap;
        private int seed;

        public SimpleHash(int cap, int seed) {
            this.cap = cap;
            this.seed = seed;
        }

        public int hash(String value) {
            int result = 0;
            int len = value.length();
            for (int i = 0; i < len; i++) {
                result = seed * result + value.charAt(i);
            }
            return (cap - 1) & result;
        }
    }

}

如何使用：

public static void main(String[] args) {
        BloomFilter bf = new BloomFilter();
        List<String> strs = new ArrayList<String>();
        strs.add("123456");
        strs.add("hello word");
        strs.add("transDocId");
        strs.add("123456");
        strs.add("transDocId");
        strs.add("hello word");
        strs.add("test");
        for (int i=0;i<strs.size();i++) {
            String s = strs.get(i);
            boolean bl = bf.contains(s);
            if(bl){
                System.out.println(i+","+s);
            }else{
                bf.add(s);
            }
      }
}