图片.png
这个题。。额。。我的大致思路就是把上部分的每个砖块质量分一半，然后加在下一层的砖块上，一直加到最后一层，再根据最大和最小的关系算个比例，求出最大压力
public class JAVA17_3 {
public static String formatFloatNumber(Double value) {
if(value != null){
if(value.doubleValue() != 0.00){
java.text.DecimalFormat df = new java.text.DecimalFormat("########.00");
return df.format(value.doubleValue());
}else{
return "0.00";
}
}
return "";
}
public static void main(String[] args) {
// TODO Auto-generated method stub
double[][] allNum = new double[30][30];
String string =
" 7 Z" +
" 5 8 Z" +
" 7 8 8 Z" +
" 9 2 7 2 Z" +
" 8 1 4 9 1 Z" +
" 8 1 8 8 4 1 Z" +
" 7 9 6 1 4 5 4 Z" +
" 5 6 5 5 6 9 5 6 Z" +
" 5 5 4 7 9 3 5 5 1 Z" +
" 7 5 7 9 7 4 7 3 3 1 Z" +
" 4 6 4 5 5 8 8 3 2 4 3 Z" +
" 1 1 3 3 1 6 6 5 5 4 4 2 Z" +
" 9 9 9 2 1 9 1 9 2 9 5 7 9 Z" +
" 4 3 3 7 7 9 3 6 1 3 8 8 3 7 Z" +
" 3 6 8 1 5 3 9 5 8 3 8 1 8 3 3 Z" +
" 8 3 2 3 3 5 5 8 5 4 2 8 6 7 6 9 Z" +
" 8 1 8 1 8 4 6 2 2 1 7 9 4 2 3 3 4 Z" +
" 2 8 4 2 2 9 9 2 8 3 4 9 6 3 9 4 6 9 Z" +
" 7 9 7 4 9 7 6 6 2 8 9 4 1 8 1 7 2 1 6 Z" +
" 9 2 8 6 4 2 7 9 5 4 1 2 5 1 7 3 9 8 3 3 Z" +
" 5 2 1 6 7 9 3 2 8 9 5 5 6 6 6 2 1 8 7 9 9 Z" +
" 6 7 1 8 8 7 5 3 6 5 4 7 3 4 6 7 8 1 3 2 7 4 Z" +
" 2 2 6 3 5 3 4 9 2 4 5 7 6 6 3 2 7 2 4 8 5 5 4 Z" +
" 7 4 4 5 8 3 3 8 1 8 6 3 2 1 6 2 6 4 6 3 8 2 9 6 Z" +
" 1 2 4 1 3 3 5 3 4 9 6 3 8 6 5 9 1 5 3 2 6 8 8 5 3 Z" +
" 2 2 7 9 3 3 2 8 6 9 8 4 4 9 5 8 2 6 3 4 8 4 9 3 8 8 Z" +
" 7 7 7 9 7 5 2 7 9 2 5 1 9 2 6 5 3 9 3 5 7 3 5 4 2 8 9 Z" +
" 7 7 6 6 8 7 5 5 8 2 4 7 7 4 7 2 6 9 2 1 8 2 9 8 5 7 3 6 Z" +
" 5 9 4 5 5 7 5 5 6 3 5 3 9 5 8 9 5 4 1 2 6 1 4 3 5 3 2 4 1 Z" +
"X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X ";
int tag1 = 0;
int tag2 = 0;
for(int i = 0; i < string.length(); i++) {
if(string.charAt(i) > '0' && string.charAt(i) <= '9') {
allNum[tag1][tag2] = Integer.parseInt(string.charAt(i)+"");
tag2++;
}
if(string.charAt(i)=='Z') {
tag1++;
tag2=0;
}
}
double halfPower=0;
for(int i = 1; i < 29; i++) {
for(int j = 1; j <= i; j++) {
halfPower = allNum[i-1][j-1]/2.0;
allNum[i][j-1]+=halfPower;
allNum[i][j] += halfPower;
}
}
double MIN = Double.MAX_VALUE;
double MAX = Double.MIN_VALUE;
for(int i = 0; i < 29; i++) {
if (allNum[28][i]>MAX) {
MAX = allNum[28][i];
}
if (allNum[28][i]<MIN) {
MIN = allNum[28][i];
}
}
System.out.print(formatFloatNumber(2086458231*MAX/MIN));
// for(double[] e:allNum) {
// for(double r:e) {
// System.out.print(r);
// }
// }
}
}
最后得出结果是36668144240.00， 应该是对的
