1031 Hello World for U (20)（20 分）

注意一下n1和n2的计算

#include<iostream>
#include<string>
using namespace std;
string s;
int main()
{
    getline(cin, s);
    int len = s.length();
    int n1 = (len+2) / 3;
    int n2 = len - 2 * n1;
    for (int i = 0; i < n1-1; i++)
    {
        printf("%c", s[i]);
        for (int k = n2; k >0; k--)printf(" ");
        printf("%c", s[len - 1 - i]);
        printf("\n");
    }
    for (int i = n1 - 1; i <= n1 + n2; i++)printf("%c", s[i]);
    return 0;
}