Leetcode 671. Second Minimum Node In a Binary Tree

文章作者:Tyan
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1. Description

Second Minimum Node In a Binary Tree

2. Solution

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    int findSecondMinimumValue(TreeNode* root) {
        int minimum = INT_MAX;
        int secondMinimum = -1;
        dfs(root, minimum, secondMinimum);
        if(secondMinimum == minimum) {
            return -1;
        }
        return secondMinimum;
    }
    
private:
    void dfs(TreeNode* root, int& minimum, int& secondMinimum) {
        if(!root) {
            return;
        }
        if(root->val < minimum) {
            minimum = root->val;
            secondMinimum = minimum;
        }
        if(root->val > minimum && (secondMinimum == minimum || root->val < secondMinimum)) {
            secondMinimum = root->val;
        }
        dfs(root->left, minimum, secondMinimum);
        dfs(root->right, minimum, secondMinimum);
    }
};

Reference

  1. https://leetcode.com/problems/second-minimum-node-in-a-binary-tree/description/
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