2020-09-02 甲级 Sign In and Sign Out

原题目 https://pintia.cn/problem-sets/994805342720868352/problems/994805516654460928

解决问题的代码：

#include<stdio.h>
#include<string.h>

/*
样例输入 
3
CS301111 15:30:28 17:00:10
SC3021234 08:00:00 11:25:25
CS301133 21:45:00 21:58:40
结果： 
SC3021234 CS301133
*/
int main()
{
    int num = 0;
    scanf("%d", &num);
    char ID[16] = "";
    char firstID[16] = "";
    char lastID[16] = "";
    int signInTime = -1;
    int signOutTime = -1;
    int firstTime = 24 * 3600;
    int lastTime = 0;
    
    int i = 0;
    for(; i < num; i++)
    {
        int h1 = 0;
        int m1 = 0;
        int s1 = 0;
        int h2 = 0;
        int m2 = 0;
        int s2 = 0;
        scanf("%s %d:%d:%d %d:%d:%d", &ID, &h1, &m1, &s1, &h2, &m2, &s2);
        signInTime = h1 * 3600 + m1 * 60 + s1;
        signOutTime = h2 * 3600 + m2 * 60 + s2;
        if(signInTime < firstTime)
        {
            strcpy(firstID, ID);
            firstTime = signInTime;
        }
        if(signOutTime > lastTime)
        {
            strcpy(lastID, ID);
            lastTime = signOutTime;
        }
        
    }

    
    printf("%s %s", firstID, lastID);
    
    return 0;
}

这道题注意两个要点：

1.时间转化为秒存储

2.数组长度不是题目说的15而至少应该是16

特别是第2点最坑，要不是我灵光一闪想起来字符串最少存储的长度应该是字符长度+1我估计还在以头撞墙。哎，赶紧记下来。