Thinking in Java第四章练习5

重复第3章中的练习10，不要用Integer.toBinaryString()方法，而是用三元操作符和按位操作符来显示二进制的1和0

这题比较有意思，写一下我的解法

package control;

import static java.lang.System.out;

public class Exercise5
{
    static final int INT_HIGH_BIT = 1 << 31;
    public static void main(String[] args) throws InterruptedException
    {
        int i = 0x2aa;
        int j = 0x555;
        out.println("i:"+toBinaryString(i));
        out.println("j:"+toBinaryString(j));
        out.println("~i:"+toBinaryString(~i));
        out.println("~j:"+toBinaryString(~j));
        out.println("(i|j):"+toBinaryString(i|j));
        out.println("(i&j):"+toBinaryString(i&j));
        out.println("(i^i):"+toBinaryString(i^i));
        out.println("(i|j):"+toBinaryString(~(i|j)));
        out.println("~(i&j):"+toBinaryString(~(i&j)));
        out.println("(i^j):"+toBinaryString(i^j));
    }

    private static String toBinaryString(int i)
    {
        String result = "";
        int j = 1;
        do {
            if (j == INT_HIGH_BIT) {
                result = ((i & j) > 0 ? "0" : "1") + result;
            } else {
                result = ((i & j) > 0 ? "1" : "0") + result;
            }
            i = i - (i & j);
            j <<= 1;
        } while (i != 0);
        
        return result;
    }
}/*Output:
i:1010101010
j:10101010101
~i:11111111111111111111110101010101
~j:11111111111111111111101010101010
(i|j):11111111111
(i&j):0
(i^i):0
(i|j):11111111111111111111100000000000
~(i&j):11111111111111111111111111111111
(i^j):11111111111
*/