codeforces-3C. Tic-tac-toe

题意：根据给定的一字棋盘，判断当前棋盘状态

#include <stdio.h>
int i;
char a[9];
bool t(char c,int i){
    
    if(a[3*i]==c&&a[3*i+1]==c&&a[3*i+2]==c
                ||a[i]==c&&a[i+3]==c&&a[i+6]==c
                        ||a[0]==c&&a[4]==c&&a[8]==c
                            ||a[2]==c&&a[4]==c&&a[6]==c)
        return true;        
    else 
            return false;   
            
}


int main(){
    
    int wo=0,wx=0,co=0,cx=0;

    for(i=0;i<9;i++){
        scanf("%c",&a[i]);
        if(a[i]=='\n'){
            i--;
            continue;
        }
        if(a[i]=='0')
            co++;
        if(a[i]=='X')
            cx++;
    }
    for(i=0;i<3;i++){
        if(t('0',i))
        wo=1;
        if(t('X',i))
        wx=1;
    }
    if((wx&&cx!=co+1)||(wo&&cx!=co)||(cx!=co+1&&cx!=co))
        printf("illegal");
    else if(wx)     
        printf("the first player won");
    else if(wo) 
        printf("the second player won");
    else if(cx+co==9) 
        printf("draw"); 
    else if(cx==co) 
        printf("first");
    else 
        printf("second");
            
    return 0;
    
}