json转换成list集合

最近在做的项目涉及到把json数据格式转换成list集合的需求，在网上看了一些文章，但是觉得比较凌乱，现在问题已经解决，特此写下此文章记录一下。

1.添加相关依赖

<!-- https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-annotations -->
        <dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-annotations</artifactId>
            <version>2.6.2</version>
        </dependency>
        <!-- https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-core -->
        <dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-core</artifactId>
            <version>2.6.2</version>
        </dependency>
        <!-- https://mvnrepository.com/artifact/org.codehaus.jackson/jackson-core-asl -->
        <dependency>
            <groupId>org.codehaus.jackson</groupId>
            <artifactId>jackson-core-asl</artifactId>
            <version>1.9.13</version>
        </dependency>
        <!-- https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-databind -->
        <dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-databind</artifactId>
            <version>2.6.2</version>
        </dependency>
        <!-- https://mvnrepository.com/artifact/org.codehaus.jackson/jackson-mapper-asl -->
        <dependency>
            <groupId>org.codehaus.jackson</groupId>
            <artifactId>jackson-mapper-asl</artifactId>
            <version>1.9.13</version>
        </dependency>

2.我们处理的json格式是如下所示：

{
    "info": [
        {
            "topoName": "mtd_recommend_dev_netty_n002",
            "weight": 50
        },
        {
            "topoName": "mtd_recommend_dev_netty_n001",
            "weight": 100
        }
    ]
}

3.具体代码实现如下：

String result=HttpRequest.sendGet(zooUrl+"gettopo",param);
        System.out.println("result--"+result);

        JSONObject obj=JSONObject.parseObject(result);//获取jsonobject对象
        System.out.println("obj---"+obj);
        JSONArray arr=obj.getJSONArray("info");//获取的结果集合转换成数组
        System.out.println("arr---"+arr);
        List list1=new ArrayList();
        for(int i=0;i<arr.size();i++){
            Map map=new HashMap();
            Map  omap=(Map) arr.get(i);
            System.out.println("omap--"+omap);
            String value1=(String) omap.get("topoName");
            System.out.println("value1--"+value1);
            Integer value2=(Integer)omap.get("weight");
            System.out.println("value2--"+value2);
            map.put("weight",value1);
            map.put("count",value2);

            list1.add(map);
        }

result就是我取到的上述json值
这就是我的实现过程，可以最终得到list集合

可以在自己的代码中去debug调试，看看是怎么一步步处理json数据的

新手，对于json并不是很了解，只是需求实现了，如有错误，欢迎指正

json转换成list集合

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