MultipartFile multfile-->byte[] fileBytes
new FileMessageResource(fileBytes, "upload.txt"));
getRestTemplate().exchange()
service逻辑
public String uploadDutyExcel(HttpServletRequest request,
@RequestParam("file") MultipartFile multfile) throws Exception {
byte[] fileBytes=multfile.getBytes();
Headers headers=new Headers();
header.setContentType(MediaType.MULTIPART_FROM_DATA)
final MultiValueMap<String,Object> data = new LinkedMultiValueMap<String,Object>();
data.add("file", new FileMessageResource(fileBytes, "upload.txt"));
final HttpEntity<MultiValueMap<String, Object>> requestEntity = new HttpEntity<MultiValueMap<String, Object>>(data);
final ResponseEntity<Map<String,String>> response = getRestTemplate().exchange(url, HttpMethod.POST, requestEntity, new ParameterizedTypeReference<Map<String,String>>() {});
}
utils.class
public class FileMessageResource extends ByteArrayResource {
/**
* The filename to be associated with the {@link MimeMessage} in the form data.
*/
private final String filename;
/**
* Constructs a new {@link FileMessageResource}.
* @param byteArray A byte array containing data from a {@link MimeMessage}.
* @param filename The filename to be associated with the {@link MimeMessage} in
* the form data.
*/
public FileMessageResource(final byte[] byteArray, final String filename) {
super(byteArray);
this.filename = filename;
}
@Override
public String getFilename() {
return filename;
}
}
