6. ZigZag Conversion
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
这个题的意思就是我们要把字符串按照锯齿形来排列，然后按行组合在一起输出。
c++:
class Solution {
public:
std::string convert(std::string s, int nRows) {
if(nRows==1)return s;
int l=s.size();
int r=0,t=1;
std::string *ss = new std::string[nRows];
for(int i=0;i<l;i++){
ss[r].push_back(s[i]);
if(r==0)t=1;
else if(r==nRows-1)t=-1;
r+=t;
}
std::string sss="";
for(int i=0;i<nRows;i++){
sss.append(ss[i]);
}
delete[] ss;
return sss;
}
};
