加密数据：
7h%1.3F3E59%.t2.n3315E35mtFxe83%16Epp%it27227563%2a%1%F56383Fm2%5%28_7AfiF2E5%966
图解凯撒列阵加密
7表示有7行，从左到右竖着看。连起来是
http%3A%2F%2Ff1.xiami.net%2F33821%2F337%5E31%2F%5E5%252%5E1768993653_6%5E6876.mp3经过urldecode后变成 http://f1.xiami.net/33821/337^31/^5%2^1768993653_6^6876.mp3把^变成0，就是 http://f1.xiami.net/33821/337031/05%201768993653_606876.mp3
逐步解析
调试图解
源码
from urllib import parse
# 解密经过加密的dataMp3内容
def dataMp3(s):
num_loc = s.find('h')
rows = int(s[0:num_loc])
strlen = len(s) - num_loc
cols = int(strlen / rows)
right_rows = strlen % rows
new_s = list(s[num_loc:])
output = ''
for i in range(len(new_s)):
x = i % rows
y = i / rows
# p = 0
if x <= right_rows:
p = x * (cols + 1) + y
else:
p = right_rows * (cols + 1) + (x - right_rows) * cols + y
output += new_s[int(p)]
return parse.unquote(output).replace('^', '0')
