给一个pattern, check true or false, 比如abbba->cdddc就是true
sol: 每个字母一种映射(hashmap)
follow up: 一次check很多string, 比如给abbba, check一个字典里面所有跟他pattern相同的,返回一个List
sol: 编码abbba->12221,然后check
class Solution {
    public List<String> findPattern(String src, String[] dict) {
        List<String> rst = new ArrayList<>();
        if (src == null || src.length() == 0 || dict == null || dict.length == 0) {
            return rst;
        }
        String sr = coding(src);
        for (String s : dict) {
            String temp = coding(s);
            if (temp.equals(sr)) {
                rst.add(s);
            }
        }
        return rst;
    }
    private String coding(String s) {
        if (s == null || s.length() == 0) {
            return s;
        }
        Map<Character, Integer> map = new HashMap<>();
        char[] rst = new char[s.length()];
        char[] src = s.toCharArray();
        int cnt = 0;
        
        for (int i = 0; i < s.length(); i++) {
            char c  = src[i];
            if (!map.containsKey(c)) {
                map.put(c, ++cnt);
            }
            rst[i] = Character.forDigit(map.get(c), 10);
        }
       
        return new String(rst);
    }
}