Advent of Code Day 8 注册表爱好者

解题语言不限Java

题目内容

You receive a signal directly from the CPU. Because of your recent assistance with jump instructions, it would like you to compute the result of a series of unusual register instructions.
你收到一条从CPU 来的消息，因为你帮助解决了跳转指令，CPU想让你帮忙计算一系列奇怪的注册表指令。

Each instruction consists of several parts: the register to modify, whether to increase or decrease that register's value, the amount by which to increase or decrease it, and a condition. If the condition fails, skip the instruction without modifying the register. The registers all start at 0. The instructions look like this:
每个命令分为几个部分，要变更的注册表项，增加或者减少指令，增加或者减少的量，还有一个条件。如果不符合条件，就跳过这个结果。所有的注册表项初始值都为零。

b inc 5 if a > 1
a inc 1 if b < 5
c dec -10 if a >= 1
c inc -20 if c == 10

These instructions would be processed as follows:
这些指令会经过一下过程。

Because a starts at 0, it is not greater than 1, and so b is not modified.
因为a的起始值是0，不大于1，所以b不会变化。
a is increased by 1(to1) becauseb is less than 5(it is 0).
a 增加1因为b小于5。
cis decreased by -10 (to 10) because a is now greater than or equal to 1 (it is 1).
c减少了-10因为a与等于1。
cis increased by-20(to -10) because c is equal to10.
c增加-20因为c与等于10。

After this process, the largest value in any register is1.
在这些步骤之后，在注册表里最大的项是1。

You might also encounter<=(less than or equal to) or!=(not equal to). However, the CPU doesn't have the bandwidth to tell you what all the registers are named, and leaves that to you to determine.
你应该考虑小于等于(<=)和不等于(!=)。但是，CPU并没有带宽告诉你所有的注册表项，这需要你自己去搞定。

What is the largest value in any register after completing the instructions in your puzzle input?
在给出的操作完成之后，最大的注册表项等于什么？

解题思路

这个题，我个人强力推荐HashMap作为储存。
基本步骤如下：

读取并解析所以的指令，具体可以按照指令的格式目标项+增减+增减量+if+条件项+条件+条件量。
在读取命令的时候，把所有的注册表项都加入到HashMap里。
按顺序运行所有命令。
运行完成之后，检查注册表值，并查找最大值。