A+B Problem too

This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
Sample Input
1 1
8600 8600
Sample Output
no
yes
定义两个整型变量A与B,
若A+B的和能被86整除，则输出yes；
若不能被86整除，则输出no。

#include<iostream>
using namespace std;
int main()
{
    int A, B;
    while (cin >> A >> B)
    {
        if ((A + B) % 86!=0)
            cout << "no" << endl;
        else
            cout << "yes" << endl;
    }
    return 0;
}