包含中文字符的NSString转换为NSURL结果为nil解决方法

使用stringByAddingPercentEncodingWithAllowedCharacters转换一下就好了

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NSString * str = @"https://www.baidu.com/s?wd=你好";
NSURL * url = [NSURL URLWithString:[str stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLFragmentAllowedCharacterSet]]];