输入一个非负整数数组，把数组里所有数字拼接起来排成一个数，打印能拼接出的所有数字中最小的一个。
LeetCode链接：https://leetcode-cn.com/problems/ba-shu-zu-pai-cheng-zui-xiao-de-shu-lcof/
class Solution:
def minNumber(self, nums: List[int]) -> str:
def quick_sort(l , r):
if l >= r: return
i, j = l, r
while i < j:
while strs[j] + strs[l] >= strs[l] + strs[j] and i < j: j -= 1
while strs[i] + strs[l] <= strs[l] + strs[i] and i < j: i += 1
strs[i], strs[j] = strs[j], strs[i]
strs[i], strs[l] = strs[l], strs[i]
quick_sort(l, i - 1)
quick_sort(i + 1, r)
strs = [str(num) for num in nums]
quick_sort(0, len(strs) - 1)
return ''.join(strs)
