Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

• The input array will only contain 0 and 1.
• The length of input array is a positive integer and will not exceed 10,000

思路：

把list通过map函数转为相应的字符串list，然后使用"".join()函数连成一个字符串，问题转为，通过"0" split之后最长的子字符串的长度。

    def findMaxConsecutiveOnes(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        return len(max("".join(map(str, nums)).split("0")))

别人解法思路：

设置两个计数器：结果值和计数值。以此访问list，如果值为1，计数值加一，结果值取结果值和计数值中的大值。如果值为0，计数值复为0。

    def findMaxConsecutiveOnes2(self, nums):
        result = 0
        count = 0

        for i in range(len(nums)):
            if nums[i] == 1:
                count += 1
                result = max(count, result)
            else:
                count = 0
        return result