1009 说反话 (20 分)

#include<stdio.h>

int main()
{
    int i=0;
    char a[100];
    int b[100];
    int countEng=0, countEngNum=0;
    char c;
    int k;

    do
    {
        c = getchar();
        a[i] = c;
        countEngNum++;
        if(c == ' ' || c== '\n')
        {
            b[countEng] = countEngNum - 1;
            countEng++;

            countEngNum = 0;
        }

        i++;
    }while(c !='\n');

    while(i >= 0)
    {

        countEng--;
        for(k=(i-1)-b[countEng];k<i-1;k++)
        {
            printf("%c", a[k]);
        }
        if(countEng>0)
            printf(" ");
        i = (i-1)-b[countEng];

    }


}