返回树结构某个子节点到根节点路径

// 根据当前id获取从根节点到该节点的路径
const getPathById = (id, data) => {
  const get = (children, target, record = []) =>
    children.reduce((result, cur) => {
      if (cur.id === target) {
        return [...record, cur]
      }
      if (cur.children && cur.children.length) {
        return [...result, ...get(cur.children, target, [...record, cur])]
      }
      return result
    }, [])

  return get(data, id)
}