8

This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
Sample Input
1 1
8600 8600
Sample Output
no
yes
问题链接：https://vjudge.net/problem/HDU-2101
问题简述：输入两个整数A跟B，判断A+B是否能被86整除，如果可以则输出yes，不行则输出no
问题分析：整型存储A,B，再输入，用if else语句判断是否可被86整除输出yes or no即可
AC通过的C++语言程序如下：

#include <iostream>
using namespace std;
int main()
{
    int a, b;
    while (cin >> a >> b)
    {
        int c = a + b;
        if (c % 86 == 0)
        {
            cout << "yes" << endl;
        }
        else cout << "no" << endl;
    }
    return 0;
}