Implement int sqrt(int x).
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Example 1:
Input: 4
Output: 2
Example 2:
Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since
the decimal part is truncated, 2 is returned.
Language: java
class Solution {
public int mySqrt(int x) {
if (x <= 1) {
return x;
}
int l = 0, r = x;
while (l <= r) {
int mid = l + (r - l) / 2;
if (x / mid < mid) {
r = mid - 1;
} else {
l = mid + 1;
}
}
return r;
}
}
Analysis：
- Binary search method
- Pay attention to the problem of integer overflow;
Submission Detail
Accepted Solutions Runtime Distribution
Accepted Solutions Memory Distribution
Language: Python
class Solution:
def mySqrt(self, x: int) -> int:
if x <= 1:
return x
l = 1
r = x
while l <= r:
mid = l + (r - l) // 2
if x // mid < mid:
r = mid - 1
else:
l = mid + 1
return r
Submission Detail
Accepted Solutions Runtime Distribution
Accepted Solutions Memory Distribution
Summary:
- Java runtime is shorter than Python;
- Java uses more memory than Python;
