本人也是初学Python，学习爬虫，不喜勿喷，纯技术交流，如有非法用途，与本人无关。有些地方可能注解的不详细，往后有时间再写的详细点，我也在继续深化脚本。希望这些微薄的经验能给你们些帮助。

#python 3.8.2

#下载网易云音乐MV

import requests

import os

import re

import json 

import urllib

import sys

def inputInt(content='请输入MV_ID()：'):

    count=0

    while count <5:

        num2 = str(input(content))

        if num2.isalpha() == 0:

            return num2

            break

        else:

            count = count + 1

            if count >= 5:

                sys.exit()

            pass

num = inputInt()       

url='http://music.163.com/mv?id=' + str(num)

headers = {

        'User-Agent':'Mozilla/5.0(Windows NT 6.3;WOW64) AppleWebKit/537.36(KHTML, like Gecko) Chrome/46.0.0.2490.80 Safari/537.36',

        'Referer':'http://93.174.95.27',

    }

req = requests.get(url, headers=headers)

req.encoding='utf-8'

try:

    pattern = re.compile(r'<script type="application/ld\+json">(.*?)</script>',re.S)#re.S(DOTALL): 点任意匹配模式，改变’.’的行为

    result = re.findall(pattern ,req.text)[0].strip()

    file_name = json.loads(result)['title']

    pattern_1 = re.compile(r'&murl=http(.*?(:?&auto))(?!\.)') #通过正则找到MV视频下载地址

    pattern2 = re.findall(pattern_1,req.text)

    if len(pattern2) == 0:

        pattern_1 = re.compile(r'hurl=http(.*?(:?&murl))(?!\.)')

        pattern2 = re.findall(pattern_1,req.text)

    elif len(pattern2) == 0:

        pattern_1 = re.compile(r'hurl=&murl=http(.*?(:?&auto))(?!\.)')

        pattern2 = re.findall(pattern_1,req.text)

    s = [str(i) for i in pattern2]

    s4 = ' '.join(s)

    url2 = urllib.parse.unquote(s4)

    s = url2.split(',')[0]

    url3 = s[3:-6]

    url4 ="http:" + url3

#url = "http://vodkgeyttp8.vod.126.net/cloudmusic/IDAiMDA2MDEwZCQxMTAgJA==/mv/5917939/f69e25b5e5da089286a29b086558e9d0.mp4?wsSecret=95a23975fe12272976a62ae67962e56b&wsTime=1584531134"

    req2 = requests.get(url4, headers = headers)

    f = open("e:\music\mv\\" + file_name + ".mp4", 'wb')

    f.write(req2.content)

    f.close()

    print(" \n %s *已成功下载，尽请聆听！\n"%(file_name))

except:

    if len(pattern2)<1:

        print(file_name + "因版权问题，无法下载，即将退出程序\n")

        sys.exit()