2018-06-14

Q1:leetcode 622
Q2:leetcode 259
Q3:leetcode 15
Q4:leetcode 18
Q5:leetcode merge interval
Q6:leetcode insert merge
Q7: leetcode 507
Q8: leetcode 1
Q9:leetcode 16
Q10:leetcode 454

class Solution {
    public int triangleNumber(int[] nums) {
        if (nums == null || nums.length == 0) {
            return 0;
        } 
        Arrays.sort(nums); //一定要sort
        int n = nums.length;
        int result = 0;
        for (int k = n - 1; k >= 2; k--) {
            int i = 0;
            int j = k - 1;
            while (i < j) { //没有去等 因为不重复用
                if (nums[i] + nums[j] <= nums[k]) {
                    i++;
                } else {
                    result += j - i;//j fixed, from i, i + 1, ...j - 1
                    j--;                }
            } 
        }
        return result;
    }
}

//Q2
class Solution {
    public int threeSumSmaller(int[] nums, int target) {
        if (nums == null || nums.length == 0) {
            return 0;
        }
        Arrays.sort(nums);
        int n = nums.length;
        int count = 0;
        for (int k = n - 1; k >= 2; k--) {
            int i = 0;
            int j = k - 1;
            while (i < j) {
                int sum = nums[i] + nums[j];
                int temptarget = target - nums[k];
                if (sum < temptarget) {
                    count += j - i;
                    i++;
                } else {
                    j--;
                }
            }
        }
        return count;
    }
}

//Q3
class Solution {
    public List<List<Integer>> threeSum(int[] nums) {
        List<List<Integer>> result = new ArrayList<>();
        if (nums == null || nums.length == 0) {
            return result;
        }
        int n = nums.length;
        Arrays.sort(nums);
       
        for (int k = n - 1; k >= 2; k--) {
            int i = 0;
            int j = k - 1;
            while (i < j) {
                int sum = nums[i] + nums[j];
                if (sum < -nums[k]) {
                    i++;
                } else if (sum > -nums[k]) {
                    j--;
                } else {
                    List<Integer> oneSol = new ArrayList<>();
                    oneSol.add(nums[i]);
                    oneSol.add(nums[j]);
                    oneSol.add(nums[k]);
                    result.add(oneSol);
                    i++;
                    while (i < j && nums[i] == nums[i - 1]) {
                    //while (i+ 1 < j && nums[i] == nums[i + 1]) {
                        i++;
                    }
                    j--;
                }
            }
            while (k - 1 > 0 && nums[k] == nums[k - 1]) {
                k--;
            }
        }
        return result;
    }
}
//
class Solution {
    public List<List<Integer>> fourSum(int[] nums, int target) {
        List<List<Integer>> result = new ArrayList<>();
        if (nums == null || nums.length == 0) {
            return result;
        }
        int n = nums.length;
        Arrays.sort(nums);
       
        for (int k = n - 1; k >= 3; k--) {
            for (int m = k - 1; m >= 2; m--) {
                int Ntarget = target - nums[k] - nums[m];
            int i = 0;
            int j = m - 1;
            while (i < j) {
                int sum = nums[i] + nums[j];
                if (sum < Ntarget) {
                    i++;
                } else if (sum > Ntarget) {
                    j--;
                } else {
                    List<Integer> oneSol = new ArrayList<>();
                    oneSol.add(nums[i]);
                    oneSol.add(nums[a]);
                    oneSol.add(nums[m]);
                    oneSol.add(nums[k]);
                    result.add(oneSol);
                    i++;
                    while (i < j && nums[i] == nums[i - 1]) {
                    //while (i+ 1 < j && nums[i] == nums[i + 1]) {
                        i++;
                    }
                    j--;
                }
            }
            
            while (m - 1 > 0 && nums[m] == nums[m - 1]) {
                m--;
            }
        }
        while (k - 1 > 0 && nums[k] == nums[k - 1]) {
                k--;
            }
        }
        return result;
    
    }
}

//Q5
if (newInterval == null) return intervals;
 boolean hasAdded =  false;
 
for (int i = 0; i < n; i++) {
      Interval cur = intervals.get(i);
      if (newInterval.start > cur.end) {
        results.add(cur);
        } else if (cur.start > newInterval.end) {
        if (!hasAdded) {
    results.add(newInterval);
    hasAdded = true;
}
results.add(cur);
} else {
    newInterval.end = Math.max(cur.end, newInterval.end);
    newInterval.start = Math.min(cur.start, newInterval.start);

}
}
if (!hasAdded) {
     results.add(newInterval);
}
return results;


//Q6
class Solution {
    public List<Interval> merge(List<Interval> intervals) {
    //TODO: null check
        Arrays.sort(intervals, new Comparator<Interval>(){
            @override
            public int compare(Interval o1, Interval o2) {
                return o1.start.CompareTo(o2.start);//Use Integer.Compare
            }
        });
        
        List<Interval> results = new ArrayList<>();
        int n = intervals.size();
        Interval temp = null;
        for (int i = 0; i < n; i++) {
            Interval cur = intervals.get(i);
            if (temp == null) {
                temp = new Interval(intervals.get(i).start, intervals.get(i).end);
            }
            if (i + 1 < n && intervals.get(i + 1).start <= temp.end) {
                temp.end = Math.max(temp.end, intervals.get(i + 1).end);
                i++;
            } else {
                results.add(temp);
                temp == null;
            }
        }

//
public class Solution {
    public boolean checkPerfectNumber(int num) {
        if (num == 1) return false;
        
        int sum = 0;
        for (int i = 2; i <= Math.sqrt(num); i++) {
            if (num % i == 0) {
                sum += i;
                if (i != num / i) sum += num / i;
            }
        }
        sum++;
        
        return sum == num;
    }
}
//
public int[] twoSum(int[] nums, int target) {
Map<Integer,Integer> hashMap = new HashMap<>();
int diff;
int result[] = new int[2];
for(int i=0;i<nums.length;i++){
diff = target - nums[i];
if(hashMap.containsKey(diff)){
result[0] = hashMap.get(diff);
result[1] = i;
break;
}else {
hashMap.put(nums[i],i);
}
}
return result;
}
//private int threeSumClosestUsingTwoPointers(int[] nums, int target) {
        
        // Sorting is essential for two pointer solution.
        Arrays.sort(nums);
        int closestThreeSum = Integer.MAX_VALUE;
        int minDistance = Integer.MAX_VALUE;
        boolean foundTarget = false;
        
        for(int i=0; i<nums.length; i++) {
            int beg=i+1;
            int end=nums.length-1;
            while(beg < end) {
                int twoSum = nums[beg] + nums[end];
                if(twoSum == target - nums[i]) {
                    closestThreeSum = target;
                    foundTarget = true;
                    break;
                }
                int possibleClosestTarget = twoSum + nums[i];
                int distanceFromTarget = Math.abs(target - possibleClosestTarget);
                if(distanceFromTarget < minDistance) {
                    minDistance = distanceFromTarget;
                    closestThreeSum = possibleClosestTarget;
                }
                if(twoSum < target - nums[i]) beg++;
                else end--;
            }
            
            if(foundTarget) break;
            
        }
        return closestThreeSum;
    }
//
public int fourSumCount(int[] A, int[] B, int[] C, int[] D) {
    /* sorting, O(n^2*log(n)) time, O(n^2) space, no map */
    int nAB = A.length * B.length;
    int[] sumAB = new int[nAB];
    int i = 0;
    for (int a : A) {
        for (int b : B) {
            sumAB[i++] = a + b;
        }
    }
    Arrays.sort(sumAB);
    int nCD = C.length * D.length;
    int[] negSumCD = new int[nCD];
    i = 0;
    for (int c : C) {
        for (int d : D) {
            negSumCD[i++] = - (c + d);
        }
    }
    Arrays.sort(negSumCD);
    // if sumAB = negSumCD, then 4 sum = 0
    i = 0;
    int j = 0;
    int res = 0;
    while (i < nAB && j < nCD) {
        if (sumAB[i] < negSumCD[j]) i++;
        else if (sumAB[i] > negSumCD[j]) j++;
        else {
            // sumAB[i] == negSumCD[j]
            // need to count number of same consecutive values, and multiply them
            int countAB = 1, countCD = 1;
            while (++i < nAB && sumAB[i-1] == sumAB[i]) countAB += 1;
            while (++j < nCD && negSumCD[j-1] == negSumCD[j]) countCD += 1;
            res += countAB * countCD;
        }
    }
    return res;
}
©著作权归作者所有,转载或内容合作请联系作者
平台声明:文章内容(如有图片或视频亦包括在内)由作者上传并发布,文章内容仅代表作者本人观点,简书系信息发布平台,仅提供信息存储服务。

推荐阅读更多精彩内容