//1. 获取 name 等于 lily 的对象
var lily = persons.filter((p) => {
return p.name == "lily";
});
console.log(lily); //打印结果 [{name: "lily", age: 16}]
//注：filter()方法返回的是一个数组
var twins = persons.filter((p) => {
return p.age == 16;
});
console.log(twins); //打印结果 [{name: "lily", age: 16},{name: "lucy", age: 16}]
