11.盛最多水的容器

题目

思路
1.取左右两侧数字
2.依次向内取最大的
3.右侧下标等于左侧时停止
代码

int maxArea(int* height, int heightSize) {
    
    int max, l, r, f, t;
    l = 0;
    r = heightSize - 1;
    if (height[l] > height[r])
    {
        max = r * height[r];
        f = 0;//右小
    }
    else
    {
        max = r * height[l];
        f = 1;//左小
    }
    int i = 1, j;
    j = r - 1;
    while(i<j)
    {
        if(f)
        {
            if(height[i] >= height[r])
            {
                t = (r - i) * height[r];
                if(t > max)
                {
                    max = t;
                    l = i;
                    f = 0;
                }
            }
            else if(height[i] > height[l])
            {
                t = (r - i) * height[i];
                if(t > max)
                {
                    max = t;
                    l = i;
                    f = 1;
                }
            }
            if(height[j] >= height[r])
            {
                t = (r - j) * height[r];
                if(t > max)
                {
                    max = t;
                    l = j;
                    f = 0;
                }
            }
            else if(height[j] > height[l])
            {
                t = (r - j) * height[j];
                if(t > max)
                {
                    max = t;
                    l = j;
                    f = 1;
                }
            }
        }
        else
        {
            if(height[i] >= height[l])
            {
                t = (i - l) * height[l];
                if(t > max)
                {
                    max = t;
                    r = i;
                    f = 1;
                }
            }
            else if(height[i] > height[r])
            {
                t = (i - l) * height[i];
                if(t > max)
                {
                    max = t;
                    r = i;
                    f = 0;
                }
            }
            if(height[j] >= height[l])
            {
                t = (j - l) * height[l];
                if(t > max)
                {
                    max = t;
                    r = j;
                    f = 1;
                }
            }
            else if(height[j] > height[r])
            {
                t = (j - l) * height[j];
                if(t > max)
                {
                    max = t;
                    r = j;
                    f = 0;
                }
            }
        }
        if (height[i] > height[j])
        {
            t = (j - i) * height[j];
            if(t > max)
            {
                max = t;
                l = i;
                r = j;
            }
            f = 0;//右小
            j--;
        }
        else
        {
            t = (j - i) * height[i];
            if(t > max)
            {
                max = t;
                l = i;
                r = j;
            }
            f = 1;//左小
            i++;
        }
    }
    return max;
}