Google官方推荐获取联系人

/**
     * 获取联系人
     */
    private void pickContact() {
        Intent pickContactIntent = new Intent(Intent.ACTION_PICK, Uri.parse("content://contacts"));
        pickContactIntent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_TYPE); // Show user only contacts w/ phone numbers
        startActivityForResult(pickContactIntent, PICK_CONTACT_REQUEST);
    }

 @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        // Check which request it is that we're responding to
        if (requestCode == PICK_CONTACT_REQUEST) {
            // Make sure the request was successful
            if (resultCode == RESULT_OK) {
                // Get the URI that points to the selected contact
                Uri contactUri = data.getData();
                // We only need the NUMBER column, because there will be only one row in the result
                String[] projection = {ContactsContract.CommonDataKinds.Phone.NUMBER};

                // Perform the query on the contact to get the NUMBER column
                // We don't need a selection or sort order (there's only one result for the given URI)
                // CAUTION: The query() method should be called from a separate thread to avoid blocking
                // your app's UI thread. (For simplicity of the sample, this code doesn't do that.)
                // Consider using CursorLoader to perform the query.
                Cursor cursor = getContentResolver()
                        .query(contactUri, projection, null, null, null);
                cursor.moveToFirst();

                // Retrieve the phone number from the NUMBER column
                int column = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
                String number = cursor.getString(column);

                // Do something with the phone number...
                Button button = findViewById(R.id.button);
                button.setText(number);
            }
        }
   }