习题6-1 分类统计字符个数 (15 分)
1. 题目摘自
https://pintia.cn/problem-sets/12/problems/308
2. 题目内容
本题要求实现一个函数,统计给定字符串中英文字母、空格或回车、数字字符和其他字符的个数。
函数接口定义:
void StringCount( char s[] );
其中 char s[]
是用户传入的字符串。函数 StringCount
须在一行内按照letter =
英文字母个数, blank =
空格或回车个数, digit =
数字字符个数, other =
其他字符个数的格式输出。
输入样例:
aZ &
09 Az
输出样例:
letter = 4, blank = 3, digit = 2, other = 1
3. 源码参考
#include<iostream>
using namespace std;
#define MAXS 15
void StringCount(char s[]);
void ReadString(char s[]);
int main()
{
char s[MAXS];
ReadString(s);
StringCount(s);
return 0;
}
void ReadString(char s[])
{
memset(s, 0, MAXS);
cin.read(s, 10);
return;
}
void StringCount(char s[])
{
char ch;
int n = strlen(s);
int letter = 0, blank = 0, digit = 0, other = 0;
for (int i = 0; i < n; i++)
{
ch = s[i];
if (((ch >= 'a') && (ch <= 'z')) || ((ch >= 'A') && (ch <= 'Z')))
{
letter++;
}
else if ((ch >= '0') && (ch <= '9'))
{
digit++;
}
else if ((ch == ' ') || (ch == '\n'))
{
blank++;
}
else
{
other++;
}
}
cout << "letter = " << letter << ", blank = " << blank << ", digit = " << digit << ", other = " << other << endl;
return;
}