JS 两个数组对象的遍历去重

记录一下两个数组对象的去重方法，方便下次偷懒。
业务大概就是，list1和list是有交集的，现在要获得list1减去list1与list2中重复的部分，即newList = list1 - (list1 ∩ list2)

var list1  =  [
  {name:'白居易',id:12},
  {name:'李商隐',id:13},
  {name:'庄周',id:830},
  {name:'老子',id:456},
  {name:'陆游',id:789}
]

var list2  =  [
  {name:'李商隐',id:13},
  {name:'老子',id:456},
  {name:'陆游',id:789},
  {name:'李白',id:77},
  {name:'杜甫',id:66}
]

let newList = [];  //保存遍历时要留下的项
      for(let len = 0; len<this.list1.length;len++){
        let item = list1[len]
        let isExist = false;
        for(var j = 0; j < list2.length; j++){
          var id = list[j].id;
          if(item.id== id){
            isExist = true;
            break;
          }
        }
        if(!isExist){
          newList.push(item);
        }
      }
      console.log(newList)  
/*[
  {name:'白居易',id:12},
  {name:'庄周',id:830}
]*/