案例
两个线程规律交替输出1，2，3，4，5，6....10
需求分析
- 线程间通信(控制线程的切换，也叫等待唤醒机制（A - 锁 - B）)
- notify()，唤醒同一锁的某个线程
- notifyAll()，唤醒同一锁的全部线程
- wait()，停止当前线程，释放锁
- wait(long timeout)，等到特定的时间，自动停止当前线程，释放锁
代码
- 定义一把公共锁
public class MyLock {
public static final Object LOCK = new Object();
}
- 定义两个线程，分别为:ThreadOne、ThreadTwo
// 线程一
public class ThreadOne extends Thread {
@Override
public void run() {
for (int i = 1; i <= 10; i += 2) {
synchronized (MyLock.LOCK) {
System.out.println(Thread.currentThread().getName() + ": " + i);
MyLock.LOCK.notify();
try {
MyLock.LOCK.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
// 线程二
public class ThreadTwo extends Thread {
@Override
public void run() {
for (int i = 2; i <= 10; i += 2) {
synchronized (MyLock.LOCK) {
System.out.println(Thread.currentThread().getName() + ": " + i);
MyLock.LOCK.notify();
try {
MyLock.LOCK.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
- 测试类
public class Test {
public static void main(String[] args) {
new ThreadOne().start();
new ThreadTwo().start();
}
}
- 结果
Thread-0: 1
Thread-1: 2
Thread-0: 3
Thread-1: 4
Thread-0: 5
Thread-1: 6
Thread-0: 7
Thread-1: 8
Thread-0: 9
Thread-1: 10
