列表和元组都是按顺序一个元素一个元素比较，不相等直接返回结果，相等就取下一个继续比较
如果所有元素都比较完了还没分出大小，那么元素多的大，元素一样多则相等
>>> ["abc", "ABC", 100, 200] == ["abc", "ABC", 100, 200]
True
>>> ["abc", "ABC", 100, 200] == ["ABC", "abc", 100, 200]
False
>>> ["abc", "ABC", 100, 200].sort() == ["ABC", "abc", 100, 200].sort()
True
>>>
>>>
>>>
>>> ["abc", 100, 300] == ["abc", 200, 200]
False
>>> ["abc", 100, 300] < ["abc", 200, 200]
True
>>> ["abc", 100, -10] > ["abc", 100]
True
>>>
>>>
>>>
>>> ("abc", "ABC", 100, 200) == ("abc", "ABC", 100, 200)
True
>>> ("abc", "ABC", 100, 200) == ("ABC", "abc", 100, 200)
False
>>>
>>>
>>>
>>> ("abc", 100, 300) == ("abc", 200, 200)
False
>>> ("abc", 100, 300) < ("abc", 200, 200)
True
>>> ("abc", 100, -10) > ("abc", 100)
True
>>>
字典同样是一个元素一个元素比较，比较的顺序和字典的 keys() 函数一致
每个元素先比 key 再比 value，都相等就取下一个
如果所有元素都比较完了还没分出大小，那么元素多的大，元素一样多则相等
>>> {"key_1":1, "key_2":2} == {"key_1":1, "key_2":2}
True
>>> {"key_3":0, "key_2":0} > {"key_1":1, "key_2":2}
True
>>> {"key_1":2, "key_2":0} > {"key_1":1, "key_2":2}
True
>>> {"key_1":1, "key_2":2, "key_3":-1} > {"key_1":1, "key_2":2}
True
>>>
集合的比较
>>> {1,2,3,4,5,6} - {1,3,5,7,9}
set([2, 4, 6])
>>> {1,2,3,4,5,6} & {1,3,5,7,9}
set([1, 3, 5])
>>> {1,2,3,4,5,6} | {1,3,5,7,9}
set([1, 2, 3, 4, 5, 6, 7, 9])
>>> {1,2,3,4,5,6} > {1,3,5,7,9}
False
>>> {1,2,3,4,5,6} > {1,3,5}
True
>>> {1,2,3} == {3,2,1}
True
>>>
