题目链接 => 戳这里

题目截图

解法

// 今天的这种做法是在原数组上直接修改值
// 因为每个元素只会被遍历使用一次，所以直接修改值得做法无关紧要
class Solution {
    public int minPathSum(int[][] grid) {
        int row = grid.length;
        int col = grid[0].length;
        for (int i = 0; i < row; i++) {
            for (int j = 0; j < col; j++) {
                if (i == 0 && j == 0) {
                    continue;
                } else if (i == 0) {
                    grid[i][j] = grid[i][j-1] + grid[i][j];
                } else if (j == 0) {
                    grid[i][j] = grid[i-1][j] + grid[i][j];
                } else {
                    grid[i][j] = Math.min(grid[i-1][j], grid[i][j-1]) + grid[i][j];
                }
            }
        }

        return grid[row-1][col-1];
    }
}