作业17-11-10

累加求和

1 #include <stdio.h>
  2 int main(){
  3     int i = 1;
  4     int sum = 0;
  5     do{
  6         sum += i;
  7         ++i;
  8     }while(i != 101);
  9     printf("总和为:%d\n",sum);
 10     return 0;
 11 }

累加求和（二）

  1 #include <stdio.h>
  2 int main(){
  3     int i = 1;
  4     int sum = 0;
  5     do{
  6         if(i%2 != 0){
  7         sum += i;
  8     }
  9         ++i;
 10     }while(i != 101);
 11     printf("总和为:%d\n",sum);
 12     return 0;
 13 }

累加求和（三）

  1 #include <stdio.h>
  2 int main(){
  3     int i = 1;
  4     int sum = 0;
  5     do{ 
  6         if(i%2 == 0){
  7         sum += i; 
  8     }   
  9         ++i;
 10     }while(i != 101);
 11     printf("总和为:%d\n",sum);
 12     return 0;
 13 }   

输入求和

  1 #include <stdio.h>
  2 int main(){
  3     int sum = 0,count = 0,bool_cin = 1;
  4     while(bool_cin){
  5         int num = 0;
  6         printf("请输入一个整数\n");
  7         scanf("%d",&num);
  8         sum += num;
  9         ++count;
 10         printf("是否继续?yes->1 no->0\n");
 11         scanf("%d",&bool_cin);
 12     }
 13     double ave = (double)sum/count;
 14     printf("和为%d,平均值为%.2g\n",sum,ave);
 15     return 0;
 16 }

看结果写程序

  1 #include <stdio.h>
  2 int main(){
  3     int num1 = 0,num2 = 0,sum = 0;
  4     printf("请输入两个整数\n");
  5     scanf("%d%d",&num1,&num2);
  6     if(num1 > num2){
  7         num1 += num2;
  8         num2 = num1-num2;
  9         num1 -= num2;
 10     }
 11     int i = 0;
 12     for(i = num1;i <= num2;i++){
 13         sum += i;
 14     }
 15     printf("大于等于%d小于等于%d的整数之和为%d\n",num1,num2,sum);
 16     return 0;
 17 }