To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase). One solution is to replace 1 (one) by @, 0 (zero) by %, l by L, and O by o. Now it is your job to write a program to check the accounts generated by the judge, and to help the juge modify the confusing passwords.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N (<= 1000), followed by N lines of accounts. Each account consists of a user name and a password, both are strings of no more than 10 characters with no space.

Output Specification:

For each test case, first print the number M of accounts that have been modified, then print in the following M lines the modified accounts info, that is, the user names and the corresponding modified passwords. The accounts must be printed in the same order as they are read in. If no account is modified, print in one line "There are N accounts and no account is modified" where N is the total number of accounts. However, if N is one, you must print "There is 1 account and no account is modified" instead.

Sample Input 1:

3
Team000002 Rlsp0dfa
Team000003 perfectpwd
Team000001 R1spOdfa

Sample Output 1:

2
Team000002 RLsp%dfa
Team000001 R@spodfa

Sample Input 2:

1
team110 abcdefg332

Sample Output 2:

There is 1 account and no account is modified

Sample Input 3:

2
team110 abcdefg222
team220 abcdefg333

Sample Output 3:

There are 2 accounts and no account is modified

分析：

简单题，循环查找字符并改动即可。
注意，由于只需要输出改动了的数据，所以每输入一组数据就尝试改动，成功就保存到结构体中，输入结束后顺序输出结构体即可。

CODE：

#include <cstdio>
#include <iostream>
#include <string>
using namespace std;

#define maxn 1010

struct p{   //结构体
    string id;
    string pass;
}a,modlist[maxn];

bool modify(string &s){  //函数负责改动，有改动就返回true
    int flag=0;
    for(unsigned int i=0;i<a.pass.length();i++){
        if(a.pass[i]=='l'){
            a.pass[i]='L';
            flag=1;
        }
        else if(a.pass[i]=='1'){
            a.pass[i]='@';
            flag=1;
        }
        else if(a.pass[i]=='0'){
            a.pass[i]='%';
            flag=1;
        }
        else if(a.pass[i]=='O'){
            a.pass[i]='o';
            flag=1;
        }
    }
    if(flag==1) return true;
    else return false;
}

int main(){
    int k;
    int mod=0;
    cin>>k;
    for(int i=0;i<k;i++){     //输入
        cin>>a.id;cin>>a.pass;
        if(modify(a.pass)==true){    //尝试改动
            modlist[mod].id=a.id;
            modlist[mod].pass=a.pass;
            mod++;
        }
    }
    if(mod==0){
        if(k==1)
            cout<<"There is 1 account and no account is modified";
        else
            cout<<"There are "<<k<<" accounts and no account is modified";
    }
    else{
        cout<<mod<<endl;
        for(int i=0;i<mod;i++){
            cout<<modlist[i].id<<" "<<modlist[i].pass<<endl;
        }
    }
    system("pause");
    return 0;
}