从请求JSON中构建ES的SearchSourceBuilder

String query = "..."
SearchSourceBuilder searchSourceBuilder = new SearchSourceBuilder();
SearchModule searchModule = new SearchModule(Settings.EMPTY, false, Collections.emptyList());
try (XContentParser parser = XContentFactory.xContent(XContentType.JSON).createParser(new NamedXContentRegistry(searchModule
            .getNamedXContents()), query)) {
    searchSourceBuilder.parseXContent(parser);
}

将请求json放到以上代码中，并通过debug模式查看构建好的searchSourceBuilder，查看构建需要哪些builder以及之间的层级关系，最后通过searchSourceBuilder.source()看下请求json是否符合原json