62圆圈中最后剩下的数字

0, 1, …, n-1这n个数字排成一个圆圈，从数字0开始每次从这个圆圈里删除第m个数字。求出这个圆圈里剩下的最后一个数字。

def LastRemaining(n, m):
    if n < 1 or m < 1:
        return -1
    result = 0
    for _ in range(2, n + 1):
        result = (result + m) % n
    return result

if __name__ == '__main__':
    assert LastRemaining(0, 5) == -1
    assert LastRemaining(5, 0) == -1
    print(LastRemaining(6, 2))
    print(LastRemaining(6, 7))
    print(LastRemaining(4000, 997))