- 1的个数
int binary1num(int x)
{
int num = 0;
while(x)
{
x = x & (x-1);
num++;
}
return num;
}
- 0的个数
int binary0num(int x)
{
int num = 0;
while(x+1)
{
x = x | (x+1);
num++;
}
return num;
}
