转换三位以内的阿拉伯数字为英文

我的解法：（基本上也就是用笨办法if出来了……主要是//整除和%取余的应用）

FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven",

            "eight", "nine"]

SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",

              "sixteen", "seventeen", "eighteen", "nineteen"]

OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",

              "eighty", "ninety"]

HUNDRED = "hundred"

def checkio(number):

    result = ""

    if number < 10:

        result = FIRST_TEN[number-1]

    elif number < 100:

        if number < 20:

            result = SECOND_TEN[number-10]

        elif number%10 == 0:

            result = OTHER_TENS[number//10-2]

        else:

            result = OTHER_TENS[number//10-2]+" "+FIRST_TEN[number%10-1]

    else:

        if number%100 in range(10,20):

            result = FIRST_TEN[number//100-1]+" "+HUNDRED+" "+SECOND_TEN[number%10]

        elif number%100 in range(1,10):

            result = FIRST_TEN[number//100-1]+" "+HUNDRED+" "+FIRST_TEN[number%100-1]

        elif number%100 == 0:

            result = FIRST_TEN[number//100-1]+" "+HUNDRED

        elif number%10 == 0:

            result = FIRST_TEN[number//100-1]+" "+HUNDRED+" "+OTHER_TENS[number%100//10-2]

        else:

            result = FIRST_TEN[number//100-1]+" "+HUNDRED+" "+OTHER_TENS[number%100//10-2]+" "+FIRST_TEN[number%10-1]

    return result

RANDOM SOLUTION

（真心惊艳！写法非常简练，涉及chain,zip,f-string用法，说实话还有点没看懂，保存下来慢慢学习！）

from itertools import chain

TWENTY = [

    '', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight',

    'nine', 'ten', 'eleven', 'twelve', 'thirteen','fourteen', 'fifteen',

    'sixteen', 'seventeen', 'eighteen', 'nineteen'

]

TENS = ['twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']

N = dict(chain(enumerate(TWENTY), zip(range(20, 91, 10), TENS)))

def checkio(n):

    n, h, u = n % 100, n // 100, n % 10

    return (f'{N[h]} hundred ' * (h>0) + N.get(n, f'{N[n-u]} {N[u]}')).strip()