2018-07-28 iOS 遍历数组，提取相同元素存入另外一个数组

NSArray *array1 = @[@"2016-10-01",@"2016-10-02",@"2016-10-03",

@"2016-10-01",@"2016-10-02",@"2016-10-03",

@"2016-10-01",@"2016-10-02",@"2016-10-03",

@"2016-10-01",@"2016-10-02",@"2016-10-03",

@"2016-10-01",@"2016-10-02",@"2016-10-03",

@"2016-10-01",@"2016-10-02",@"2016-10-03",

@"2016-10-04",@"2016-10-06",@"2016-10-08",

@"2016-10-05",@"2016-10-07",@"2016-10-09"];

NSMutableArray *array= [NSMutableArray arrayWithArray:array1];

    NSMutableArray *dateMutablearray = [@[] mutableCopy];

for(inti =0; i

NSString *string=array[i];

        NSMutableArray *tempArray = [@[] mutableCopy];

[tempArray addObject:string];

for(intj = i+1; j

NSString *jstring =array[j];

if([stringisEqualToString:jstring]){

                [tempArray addObject:jstring];

[arrayremoveObjectAtIndex:j];

j -=1;

            }

        }

        [dateMutablearray addObject:tempArray];

    }

NSLog(@"dateMutable:%@",dateMutablearray);

©著作权归作者所有,转载或内容合作请联系作者
平台声明：文章内容（如有图片或视频亦包括在内）由作者上传并发布，文章内容仅代表作者本人观点，简书系信息发布平台，仅提供信息存储服务。

推荐阅读更多精彩内容