合并两个字典
{a,b}
dict(a,b)
dict({'counter': result[grade['grade']]}, **grade)
list(map(lambda grade: dict({'counter': result[grade['grade']]}, **grade), grades))
list(map(lambda x: x+1, list(filter(lambda x: x != [], reduce(lambda x, y: x+y, list(gridRankGroupByHour[gridId][index].values()))))))
gridHourAQDataGroupById = gridHourAQData.groupby(['grid_id'])
dayAQData = gridHourAQDataGroupById.mean()
获取每个网格对应的o3和时间的详细信息并组成列表
dayAQData_o3 = [gridHourAQDataGroupById['o3', 'published_at'].get_group(x) for x in range(1, 4901)]
获取分组信息
gridHourAQDataGroupById['o3', 'published_at'].get_group(x)
dayAQData['grid_tags'] = list(map(lambda x: gridHourAQData.drop_duplicates(subset='grid_id').loc[gridHourAQData['grid_id'] == x, 'tags'].to_numpy()[0], gridHourAQData['grid_id'].unique()))
使用reduce
areaAQDataGroupById = list(map(lambda x: x['id'], areas))
在第一项插入一个空字典
areaAQDataGroupById.insert(0, {})
合并字典从而达到键值对的效果
areaAQDataGroupById = reduce(lambda x, y: dict({str(y): []}, **x), areaAQDataGroupById)
