js获取url参数

    var url = "https://xxx.com?user=tom&age=20&gender=male&score=100&score=90"
    function getParams(url) {  
        let urlPramas = url.split("?")[1].split("&");
        let obj = {};
        for(let i of urlPramas){
            let arr = i.split("=");
            var [name,val] = arr;
            if(obj[name] == undefined){
                obj[name] = val
            }else{
                obj[name]=[].concat(val,obj[name])
            }
        }
        return obj;
    }
    console.log(getParams(url))

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