Erlang 使用rfc4627处理list

1. 基础用法,单个转换

Obj 结构如下:

{obj,[{name,jack},{age,20}]}

基本用法:

fc4627:encode(Obj).

例子:

12> Obj = {obj,[{name,jack},{age,20}]}.

{obj,[{name,jack},{age,20}]}

13> Json = rfc4627:encode(Obj).

"{\"name\":\"jack\",\"age\":20}"

14> io:format(Json).

{"name":"jack","age":20}ok

2.处理一组Obj:

Obj list 结构:

{obj,[{lists,[{obj,[{name,jack},{age,20}]},{obj,[{name,tony},{age,21}]}]}]}

例子:

19> A = {obj,[{name,jack},{age,20}]}.

{obj,[{name,jack},{age,20}]}

20> B = {obj,[{name,tony},{age,21}]}.

{obj,[{name,tony},{age,21}]}

21> List = {obj, [{lists, [A, B]}]}.

{obj,[{lists,[{obj,[{name,jack},{age,20}]},

{obj,[{name,tony},{age,21}]}]}]}

23> Json = rfc4627:encode(List).

"{\"lists\":[{\"name\":\"jack\",\"age\":20},{\"name\":\"tony\",\"age\":21}]}"

24> io:format(Json).

{“lists":[{"name":"jack","age":20},{"name":"tony","age":21}]}

3. 一组record转json例子:

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