**1.【编码实现】去除一个整数数组中的重复元素，并进行从大到小排序，最后打印出结果。**
参考答案：
```python
def qchong(s):
list1 = []
for num in s:
if num not in list1:
list1.append(num)
return sorted(list1, reverse=True)
if __name__ == "__main__":
s = [12, 16, 15, 18, 26, 18, 17, 16]
res = qchong(s)
print(res)
# out [26, 18, 17, 16, 15, 12]
```
**2.【编码实现】提取如下html结构中的信息。**
```python
<div class="list">
<div class="item">
<p><label>姓名：</label><span>蔡徐坤</span></p>
<p><label>类型：</label><span>human</span></p>
<p><label>年龄：</label><span>24</span></p>
</div>
<div class="item">
<p><label>姓名：</label><span>伊娃</span></p>
<p><label>类型：</label><span>机器人</span></p>
<p><label>生产日期：</label><span>2019-01-01</span></p>
</div>
<div class="item">
<p><label>姓名：</label><span>豆豆</span></p>
<p><label>类型：</label><span>动物</span></p>
<p><label>年龄：</label><span>3</span></p>
</div>
<div class="item">
<p><label>姓名：</label><span>鹿晗</span></p>
<p><label>类型：</label><span>人类</span></p>
<p><label>年龄：</label><span>21</span></p>
</div>
</div>
```
并生成如下数据结构：
{
'human': [{ age: 24, name: '蔡徐坤' },{ age: 21, name: '鹿晗' }],
'robot': [{ dateTime: '2019-01-01', name: '伊娃' }],
'animal': [{ age: 3, name: '豆豆' }],
}
参考答案：
```python
from lxml import etree
if __name__ == "__main__":
content = """
<div class="list">
<div class="item">
<p><label>姓名：</label><span>蔡徐坤</span></p>
<p><label>类型：</label><span>human</span></p>
<p><label>年龄：</label><span>24</span></p>
</div>
<div class="item">
<p><label>姓名：</label><span>伊娃</span></p>
<p><label>类型：</label><span>机器人</span></p>
<p><label>生产日期：</label><span>2019-01-01</span></p>
</div>
<div class="item">
<p><label>姓名：</label><span>豆豆</span></p>
<p><label>类型：</label><span>动物</span></p>
<p><label>年龄：</label><span>3</span></p>
</div>
<div class="item">
<p><label>姓名：</label><span>鹿晗</span></p>
<p><label>类型：</label><span>人类</span></p>
<p><label>年龄：</label><span>21</span></p>
</div>
</div>
"""
page = etree.HTML(content)
items = page.xpath('.//div[@class="item"]')
all_content = {}
people = []
robot = []
animal = []
for item in items:
nr = item.xpath('./p/span/text()')
if 'human' in nr or '人类' in nr:
# print(i)
people.append({'age': nr[2], 'name': nr[0]})
elif '机器人' in nr:
robot.append({'dateTime': nr[2], 'name': nr[0]})
else:
animal.append({'age': nr[2], 'name': nr[0]})
all_content['human'] = people
all_content['robot'] = robot
all_content['animal'] = animal
print(all_content)
out = {'human': [{'age': '24', 'name': '蔡徐坤'}, {'age': '21', 'name': '鹿晗'}],
'robot': [{'dateTime': '2019-01-01', 'name': '伊娃'}],
'animal': [{'age': '3', 'name': '豆豆'}]}
```
**3.【编码实现】有如下数组，需要将每个字符串中排列在任意x前面的所有y替换为0，请计算并打印出每个字符串需要被替换的y的个数。**
arr = ['xxyyxyyyyyxxx', 'yxxxx', 'xyyyxxyx', 'xxxx', 'xxxyyy'];
```python
import re
def change_str(listi):
list_res = []
pattern = re.compile(r'(y+)x')
for s in listi:
res = re.findall(pattern, s)
list_res.append(len(''.join(res)))
return list_res
if __name__ == "__main__":
arr = ['xxyyxyyyyyxxx', 'yxxxxyxy', 'xyyyxxyx', 'xxxx', 'xxxyyy'];
res = change_str(arr)
print(res)
# out = [7, 2, 4, 0, 0]
```
