已知一个数字列表,求列表中心元素。
count = 0
new_list = [1,2,3,4,5]
if len(new_list)%2 == 0:
print(new_list[len(new_list)//2-1:len(new_list)//2+1])
else:
print(new_list[len(new_list)//2:len(new_list)//2+1])
已知一个数字列表,求所有元素和。
num1 = 0
list1 = [1,2,3,4,5,6,123213]
for num in list1:
num1 += num
print(num1)
已知一个数字列表,输出所有奇数下标元素。
list1 = [1,2,3,4,5,6,123213,1,2,3,4]
count = 0
for num in list1:
count += 1
if count%2 != 0:
del list1[count-1]
print(list1)
已知一个数字列表,输出所有元素中,值为奇数的。
list1 = [1,2,3,4,5,6,123213,1,2,3,4]
count = 0
for num in list1:
count += 1
if num %2 != 1:
del list1[count-1]
print(list1)
已知一个数字列表,将所有元素乘二。
例如:nums = [1, 2, 3, 4] —> nums = [2, 4, 6, 8]
count = 0
list1 = [1,2,3,4,5,6,123213,1,2,3,4]
for num in list1:
count += 1
list1[count-1] *= 2
print(list1)
有一个长度是10的列表,数组内有10个人名,要求去掉重复的
例如:names = ['张三', '李四', '大黄', '张三'] -> names = ['张三', '李四', '大黄']
count = 1
names = ['张三', '李四', '大黄', '张三','张三', '李四', '大黄', '张三', '大黄', '张三']
for name1 in names:
for name in names[count:11:1]:
if name == name1:
names.remove(name1)
count += 1
print(names)
已经一个数字列表(数字大小在0~6535之间), 将列表转换成数字对应#的字符列表
例如: list1 = [97, 98, 99] -> list1 = ['a', 'b', 'c']
list0 = [ ]
count = 0
list1 = [1,72,37,4,5,76,1,17,2,37,4]
for num in list1:
count += 1
list0 += list(chr(list1[count-1]))
print(list0)
.用一个列表来保存一个节目的所有分数,求平均分数(去掉一个最高分,去掉一个最低分,求最后得分)
scores3 = 0
count = 0
scores1 = [60,12,55,67,89,90,87]
for scores2 in scores1:
count += 1
scores3 += scores2
print((scores3-min(scores1)-max(scores1))/count)
有两个列表A和B,使用列表C来获取两个列表中公共的元素
例如: A = [1, 'a', 4, 90] B = ['a', 8, 'j', 1] --> C = [1, 'a']
A = [1, 'a', 4, 90,8,34,45]
B = ['a', 8, 'j', 1,834,8]
count1 = 0
count2 = 0
C = []
for num1 in A :
for num2 in B:
if num1 == num2:
count1 += 1
if count1 == 1:
C += [num1]
print(C)
有一个数字列表,获取这个列表中的最大值.(注意: 不能使用max函数)
例如: nums = [19, 89, 90, 600, 1] —> 600
nums = [19, 89, 90, 1,600, 100011,787900]
for num1 in nums:
for num2 in nums:
if num2 > num1:
break
else:
print(num1)