前言
在java开发中,用Jpa框架做连表查询时(需要返回两张表的各自部分字段),在返回对象的过程中感觉比较棘手,一直没有一个好的解决方案,网上也有各种版本的方法,下面的方法本人感觉最方便使用
1、创建一个SpringBoot空白项目,引入pom依赖
先看项目结构,为了简化,没有引入service层,直接使用controller调用dao层
pom.xml配置
<!-- web依赖 -->
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<!-- lombok依赖 -->
<dependency>
<groupId>org.projectlombok</groupId>
<artifactId>lombok</artifactId>
<version>1.18.8</version>
</dependency>
<!-- jpa依赖 -->
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-jpa</artifactId>
</dependency>
<!-- mysql依赖 -->
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<scope>runtime</scope>
</dependency>
2、application.yml配置文件
server:
port: 13333
spring:
datasource:
url: jdbc:mysql://localhost:3306/test?characterEncoding=UTF-8&autoReconnect=true&serverTimezone=Asia/Shanghai&zeroDateTimeBehavior=convertToNull
username: root
password: 12345678
driver-class-name: com.mysql.jdbc.Driver
jpa:
show-sql: true
hibernate:
ddl-auto: none
3、数据库(有两张表user/address)
我们现在需要联查user和address表,address表中的user_id是和user表中id是做关联查询
4、User.java 和 Address.java
5、UserDaoRepository.java 和 AddressDaoRepository.java
附上UserDaoRepository.java的代码
package com.lss.jpa.dao;
import com.lss.jpa.entity.dto.UserAddressDto;
import com.lss.jpa.entity.po.User;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.jpa.repository.Query;
import java.util.List;
import java.util.Map;
public interface UserDaoRepository extends JpaRepository<User, Integer> {
@Query(value = "select \"title\" as common, u.id as id, u.name as name, a.id as addressId, a.address as addressName from user u, address a where u.id = a.user_id", nativeQuery = true)
public List<UserAddressDto> findAllUserAddress();
@Query(value = "select \"title\" as common, u.id as id, u.name as name, a.id as addressId, a.address as addressName from user u, address a where u.id = a.user_id and u.id=1", nativeQuery = true)
public UserAddressDto findAllUserAddressById();
@Query(value = "select \"title\" as common, u.id as id, u.name as name, a.id as addressId, a.address as addressName from user u, address a where u.id = a.user_id and u.id=1", nativeQuery = true)
public Map<String, Object> findAllUserAddressByMap();
}
5、UserAddressDto.java代码
package com.lss.jpa.entity.dto;
public interface UserAddressDto {
Integer getId();
String getName();
String getAddressName();
Integer getAddressId();
String getCommon();
}
此处我们自定义了UserAdressDto来接收两张表返回的数据,注意:此时创建的是一个interface,并且里面的字段是用get的形式创建的接收参数
6、TestController.java
package com.lss.jpa.web;
import com.lss.jpa.dao.UserDaoRepository;
import com.lss.jpa.entity.dto.UserAddressDto;
import com.lss.jpa.entity.po.User;
import lombok.extern.slf4j.Slf4j;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RestController;
import java.util.List;
import java.util.Map;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;
@RestController
@Slf4j
public class TestController {
@Autowired
private UserDaoRepository userDaoRepository;
@GetMapping("test")
public String test(){
List<UserAddressDto> all = userDaoRepository.findAllUserAddress();
all.stream().forEach(dto -> {
log.info("result: id:{}, name:{}, addressId:{}, addressName:{}, common:{}", dto.getId(), dto.getName(), dto.getAddressId(), dto.getAddressName(), dto.getCommon());
});
UserAddressDto dto = userDaoRepository.findAllUserAddressById();
log.info("result: id:{}, name:{}, addressId:{}, addressName:{}, common:{}", dto.getId(), dto.getName(), dto.getAddressId(), dto.getAddressName(), dto.getCommon());
Map<String, Object> map = userDaoRepository.findAllUserAddressByMap();
log.info("map:{}", map);
List<User> userList = userDaoRepository.findAll();
log.info("userList:{}", userList);
return "ok";
}
}
最后,启动项目,调用/test接口
curl http://localhost:13333/test
看console里打印结果
Hibernate: select "title" as common, u.id as id, u.name as name, a.id as addressId, a.address as addressName from user u, address a where u.id = a.user_id
2020-02-23 13:14:33.293 INFO 2816 --- [io-13333-exec-3] com.lss.jpa.web.TestController : result: id:1, name:zhangsan , addressId:1, addressName:beijing, common:title
2020-02-23 13:14:33.293 INFO 2816 --- [io-13333-exec-3] com.lss.jpa.web.TestController : result: id:2, name:lisi, addressId:2, addressName:tianjin, common:title
Hibernate: select "title" as common, u.id as id, u.name as name, a.id as addressId, a.address as addressName from user u, address a where u.id = a.user_id and u.id=1
2020-02-23 13:14:33.296 INFO 2816 --- [io-13333-exec-3] com.lss.jpa.web.TestController : result: id:1, name:zhangsan , addressId:1, addressName:beijing, common:title
Hibernate: select "title" as common, u.id as id, u.name as name, a.id as addressId, a.address as addressName from user u, address a where u.id = a.user_id and u.id=1
2020-02-23 13:14:33.299 INFO 2816 --- [io-13333-exec-3] com.lss.jpa.web.TestController : map:org.springframework.data.jpa.repository.query.AbstractJpaQuery$TupleConverter$TupleBackedMap@72cce81
Hibernate: select user0_.id as id1_1_, user0_.name as name2_1_ from user user0_
2020-02-23 13:14:33.305 INFO 2816 --- [io-13333-exec-3] com.lss.jpa.web.TestController : userList:[User(id=1, name=zhangsan ), User(id=2, name=lisi), User(id=3, name=wangwu), User(id=4, name=zhaoliu)]
我们可以拷到输出的sql和联查出来的数据结果,都被dto完美接收