关于将集合根据某个属性转Map的问题

Java分组

• lombda分组为List<Object,List<Object>>

list.stream().collect(Collectors.groupingBy(SlhEvaluationAssignment::getTeamId));

• 将集合某个字段作为Map的key，实体本身作为value，数据格式为Map<Object,Object>

list.stream().collect(Collectors.toMap(Apple::getId, a -> a,(k1,k2)->k1));

• 获取分组后的值

for (Map.Entry<Integer, List<SlhEvaluationAssignment>> entry : collect.entrySet()) {
    Integer teamId = entry.getKey();
    List<SlhEvaluationAssignment> slhEvaluationAssignmentList = entry.getValue();
}

JS

• 将数组某个字段作为{}的属性，实体本身作为属性值转为对象

let data = Object.fromEntries(array.map(item => [item.frequency, item]))
// 取值
data['分组的字段值']

• 前端多字段过滤

/**
 * 前端多字段过滤(入参分别为：原数组、检索的值、检索字段如['id','name'])
 */
search(arr, query, key = []) {
      return arr.filter(v => Object.values(Object.fromEntries(Object.entries(v).filter(item => (key.length ? key.includes(item[0]) : true)))).some(v => new RegExp(query + '').test(v)))
    },