iOS开发 - APP间通讯

常用的APP间通讯场景是支付和分享。接入支付宝等支付场景时需要跳转到支付宝APP，完成支付后再将支付结果返回原来的APP，这样就涉及APP间传值。

新建App1和App2两个应用，如果我想从App1调起App2，那么我需要添加App2的URL Scheme，不同于其他手机APPs的值，用来在App1发起openUrl方法时找到手机里的App2应用。

设置App2的URL Scheme为AppTwoScheme

App1想要调起App2时只需要通过如下方法即可

NSURL *url = [NSURL URLWithString: [NSString stringWithFormat: @"AppTwoScheme://com.zy.app1/subpath?para=%i&from=%@", 1, @"app1"]];
if ([[UIApplication sharedApplication] canOpenURL: url]) {
    NSLog(@"canOpenUrl");
    if (@available(iOS 10, *)) {
        NSDictionary *options = @{UIApplicationOpenURLOptionsSourceApplicationKey : @YES};
        [[UIApplication sharedApplication] openURL: url options: options completionHandler: nil];
    }else{
        [[UIApplication sharedApplication] openURL: url];
    }
}

从iOS 10开始，还需要在App1中添加白名单LSApplicationQueriesSchemes数组

在App2的AppDelegate代理方法中接收传入的值，如果使用SceneDelegate类，则在-(void)scene:(UIScene *)scene openURLContexts:(NSSet<UIOpenURLContext *> *)URLContexts代理方法中接收。

-(BOOL)application:(UIApplication *)app openURL:(NSURL *)url options:(NSDictionary<UIApplicationOpenURLOptionsKey,id> *)options
{
    UIAlertController *alertVC = [UIAlertController alertControllerWithTitle: @"提示" message: @"收到一条从APP1传来的简讯" preferredStyle: UIAlertControllerStyleAlert];
    [self.window.rootViewController presentViewController: alertVC animated: YES completion: nil];
    NSLog(@"absoulteString: %@", url.absoluteString);
    NSLog(@"scheme: %@", url.scheme);
    NSLog(@"host: %@", url.host);
    NSLog(@"path: %@", url.path);
    NSLog(@"query: %@", url.query);
    NSLog(@"Url参数: %@", [self getURLParameters: url.absoluteString]);
    if ([url.host isEqualToString: @"com.zy.app1"]) {
        //从app1跳转过来
    }
    return YES;
}

scheme、host和query等结果如下：

若需要将App2中的处理结果返回给App1，同样的操作：设置App1的URL Scheme为AppOneScheme，添加App2的白名单为AppOneScheme，给App2一个触发事件调用

UIAlertController *alertVC = [UIAlertController alertControllerWithTitle: @"提示" message: @"收到一条从APP1传来的简讯" preferredStyle: UIAlertControllerStyleAlert];
[alertVC addAction: [UIAlertAction actionWithTitle: @"确定" style: UIAlertActionStyleDefault handler:^(UIAlertAction * _Nonnull action) {
        NSURL *oneUrl = [NSURL URLWithString: [NSString stringWithFormat: @"AppOneScheme://com.zy.app2?result=1"]];
        if (@available(iOS 10, *)) {
            [[UIApplication sharedApplication] openURL: oneUrl options: @{} completionHandler: nil];
        }else{
            [[UIApplication sharedApplication] openURL: oneUrl];
        }
 }]];
 [self.window.rootViewController presentViewController: alertVC animated: YES completion: nil];

App1接收到的返回值为

-(void)scene:(UIScene *)scene openURLContexts:(NSSet<UIOpenURLContext *> *)URLContexts
{
    if (URLContexts.count > 0) {
        NSEnumerator *enumerator = [URLContexts objectEnumerator];
        UIOpenURLContext *urlContext = [enumerator nextObject];
        NSURL *url = urlContext.URL;
        NSLog(@"absoulteString: %@", url.absoluteString);
        NSLog(@"scheme: %@", url.scheme);
        NSLog(@"host: %@", url.host);
        NSLog(@"path: %@", url.path);
        NSLog(@"query: %@", url.query);
        NSLog(@"Url参数: %@", [self getURLParameters: url.absoluteString]);
        if ([url.host isEqualToString: @"com.zy.app2"]) {
            //从app2返回的数据
        }
    }
}

如此，即完成了一组App间的传值。

但要注意，如果从左上角的返回按钮回到App1则无法将结果返回，因为没有调用openURL吧。